Let ABCD be a cyclic quadrilateral with sides AB = 2 cm, BC = 7 cm, CD = 11 cm, DA = 14 cm. Find the product of its diagonals.

125 cm

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120 cm

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364 cm

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34 cm

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Solution

The correct option is B 120 cm
Using Ptolemy's theorem,
$A C \times B D = (A B \times C D) + (A D \times B C)$
Substituting the values,
AC × BD = (2 × 11) + (14 × 7)
=120 cm

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