Let ABCD be a rectangle and E and F be the points on CD and BC respectively such that area of (△ADE)=16, area (△CEF)=9 and area (△ABC)=25. What is the area of △AEF?
A
<25
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B
>30
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C
<32
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D
>36
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Solution
The correct option is A<25 area(△ABC)=25sq.units ⇒ Area of ABCD=50sq.units area(ADE)+area(△CEF)=16+9=25sq.units ∴area(AEFB)=25sq.units Hence, area(AEF) must be less than 25sq.units