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Standard XII

Mathematics

Basic Inverse Trigonometric Functions

Let ABCD be a...

Question

Let ABCD be a square. E and F be points on AC such that AE = EF = FC =AC/3. Then tan (ÐEBF) equals :

\frac{3}{4}

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\frac{1}{\sqrt{3}}

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\frac{1}{2}

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\frac{1}{3}

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Solution

The correct option is A $\frac{3}{4}$

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Similar questions

Q. Let

A B C D

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and

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A E = E F = F C = \frac{A C}{3}

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Q. In trapezium

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\frac{A E}{E D} = \frac{B F}{F C}

ABCD is a trapezium with $A B ∥ D C$ . E and F are points on non-parallel sides AD and BC respectively such that $E F ∥ A B$ . Show that $\frac{A E}{E D} = \frac{B F}{F C}$ .

Q. ABCD is trapezium with AB||DC. E and F are points on non-parralel sides AD and BC respectively such that EF||AB. Show that AE/ED=BF/FC.

In quadrilateral ABCD, diagonals AC and BD intersect at point E. Such that AE : EC = BE : ED. Then, ABCD is a parallelogram.

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Let ABCD be a square. E and F be points on AC such that AE = EF = FC =AC/3. Then tan (ÐEBF) equals :

The correct option is A 34

The correct option is A $\frac{3}{4}$