Let ABCD be a trapezium, in which AB is parallel to CD,AB=11,BC=4,CD=6 and DA=3. The distance between AB and CD is
Let ABCD be a quadrilateral with diagonals AC and BD. Prove the following statements (Compare these with the previous problem);
(a) AB + BC + CD > AD;
(b) AB + BC + CD + DA > 2AC;
(c) AB + BC + CD + DA > 2BD;
(d) AB + BC + CD + DA > AC + BD.