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Question

Let ABCD be the parallelogram whose sides ABand AD are represented by the vectors 2i^+4j^-5k^ and i^+2j^+3k^ respectively. Then, if a is a unit vector parallel to AC, then a is equal to ?


A

3i^-6j^-2k^3

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B

3i^+6j^+2k^3

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C

3i^-6j^-2k^7

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D

3i^+6j^-2k^7

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Solution

The correct option is D

3i^+6j^-2k^7


Explanation for the correct option:

Calculating the value of a:

Let ABCD be the parallelogram.

Given that,

AB=2i^+4j^-5k^AD=i^+2j^+3k^

AC is the diagonal of a given parallelogram. Then by the parallelogram law, we get :

AC=AB+AD=2i^+4j^-5k^+i^+2j^+3k^=3i^+6j^-2k^

The unit vector a^ parallel to AC is a^=ACAC.

Now,

AC=32+62+-22=49=7

Therefore, a=3i+6j-2k7.

Hence, option (D) is the correct answer.


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