Let α1,α2 and β1,β2 be the roots of ax2+bx+c=0 and px2+qx+r=0 respectively. If the system of equations α1y+α2z=0 and β1y+β2z=0 has a non-trivial solution, then which of the following options is CORRECT ?
A
abc=pqr
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B
a2pr=q2bc
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C
b2pr=q2ac
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D
a2qr=p2bc
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Solution
The correct option is Cb2pr=q2ac ax2+bx+c=0 ⇒α1+α2=−ba,α1α2=ca and px2+qx+r=0 ⇒β1+β2=−qp,β1β2=rp
α1y+α2z=0,β1y+β2z=0 have a non-trivial solution. ∴∣∣∣α1α2β1β2∣∣∣=0