wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Let α1,α2 and β1,β2 be the roots of ax2+bx+c=0 and px2+qx+r=0 respectively. If the system of equations α1y+α2z=0 and β1y+β2z=0 has a non-trivial solution, then which of the following options is CORRECT ?

A
abc=pqr
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
a2pr=q2bc
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
b2pr=q2ac
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
a2qr=p2bc
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C b2pr=q2ac
ax2+bx+c=0
α1+α2=ba, α1α2=ca
and px2+qx+r=0
β1+β2=qp, β1β2=rp

α1y+α2z=0, β1y+β2z=0 have a non-trivial solution.
α1α2β1β2=0

α1β2α2β1=0
α1β1=α2β2=k (say)

Now, α1+α2=ba
k(β1+β2)=ba
k(qp)=ba
k=pbqa (1)

α1α2=ca
k2β1β2=ca
k2(rp)=ca
k2=pcar (2)

From (1) and (2),
p2b2q2a2=pcar
b2pr=q2ac

flag
Suggest Corrections
thumbs-up
9
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon