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Question

Let α and β be non zero real numbers such that 2(cosβcosα)+cosαcosβ=1. Then which of the following is/are true?

A
3tan(α2)tan(β2)=0
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B
tan(α2)3tan(β2)=0
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C

tan(α2)+3tan(β2)=0
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D
3tan(α2)+tan(β2)=0
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Solution

The correct options are
B tan(α2)3tan(β2)=0
C
tan(α2)+3tan(β2)=0
We have, 2(cosβcosα)+cosαcosβ=1
Or 4(cosβcosα)+2cosαcosβ=2
1cosα+cosβcosαcosβ
=3+3cosα3cosβ3cosααcosβ
(1cosα)(1+cosβ)=3(1+cosα)(1cosβ)
(1cosα)(1+cosα)=3(1cosβ)(1+cosβ)
tan2α2=3tan2β2
tanα2±3tanβ2=0

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