Let α and β be the roots of x2−x−1=0,with α > β, For all positive integers n, define, an=αn−βnα−β,n≥1 b1=1 and bn=an−1+an+1,n≥2.
Then which of the following option is/are correct?
A
a1+a2+a3+......+an=an+2−1 such thatn≥1
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B
∞∑n=1an10n=1089
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C
∞∑n=1bn10n=889
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D
bn=αn+βn such that n≥1
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Solution
The correct option is Dbn=αn+βn such that n≥1 α,β are roots of equation x2−x−1=0,
So, α+β=1,α⋅β=−1, α,β=+1±√52,α−β=√5 α2=(1+√52)2=3+√52 β2=(1−√52)2=3−√52
L.H.S =a1+a2+a3+......+an =(α+α2+α3+...+αn)−(β+β2+β3+...+βn)α−β =α(1−αn)(α−β)(1−α)−β(1−βn)(α−β)(1−β) α2−α−1=0⇒α2−1=α⇒α+1=−α1−α =(−(α+1)(1−αn))+(1+β)(1−βn)α−β =−α2(1−αn)+β2(1−βn)α−β=(αn+2−βn+2)+(β2−α2)α−β =αn+2−βn+2α−β−α2−β2α−β=an+2−(α+β)=an+2−1