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Question

Let α,β be the roots of the equation (xa)(xb)=c,c0. Then the roots of the equation (xα)(xβ)+c=0 are

A
a+c, b+c
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B
b,c
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C
a,b
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D
a,c
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Solution

The correct option is C a,b
(xa)(xb)c=(xα)(xβ)(xα)(xβ)+c=(xa)(xb)c+c=(xa)(xb)
Then the roots of (xα)(xβ)+c=0 are
x=a,b

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