Question

Let $\alpha ,\beta$ be the roots of the equation (x - a) (x - b) = c, c $\ne$ 0. Then the roots of the equation $(x-\alpha )(x-\beta )+c=0$ are

• A. a, c
• B. b, c
• C. a, b
• D. a + c, b + c

Answer 1

The correct option is C a, b

$\because (x-a)(x-b)-c=(x-\alpha )(x-\beta )\therefore (x-\alpha )(x-\beta )+c=(x-a)(x-b)-c+c=(x-a)(x-b)$
Then the roots of $(x-\alpha )(x-\beta )+c=0$ are
x = a, b