Let α,β be the values of m for which the equation (1+m)x2−2(1+3m)x+(1+8m) has equal roots. Find the equation whose roots are α+2 and β+2.
A
x2−4x+3=0
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B
x2−5x+6=0
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C
x2−3x=0
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D
x2−7x+10=0
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Solution
The correct option is D
x2−7x+10=0
△=0⇒(2(1+3m))2−4(1+m)(1+8m)=0 ⇒1+9m2+6m−1−9m−8m2=0 ⇒m2−3m=0 ⇒m(m−3)=0 ⇒α=0,β=3 ⇒α+2=2 and β+2=5
Equation whose roots are α+2 and β+2 is (x−2)(x−5)=x2−7x+10=0