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Question

Let < an > be a sequence defined by
a1 = 3
and, an = 3an − 1 + 2, for all n > 1
Find the first four terms of the sequence.

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Solution

Given:
a1 = 3
And, an = 3an − 1 + 2 for all n > 1

a2 = 3a2-1+2 = 3a1+2 = 11a3 = 3a3-1+2 = 3a2+2 = 35a4 = 3a4-1+2 = 3a3+2 = 107Thus, the first four terms of the sequence are 3, 11, 35, 107.

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