Let ∗ be a binary operation on the set Q of rational number as follows:
(iii)a∗b=a+ab
Show that none of the operations has an identity.
An element e∈Q will be the identity element for the operation ∗ if
a∗b=a+ab
If a ∗e=a⇒a+ae=a⇒ae=0⇒e=0,a≠0
Also if
⇒e∗a=a⇒e+ea=a⇒e=a1−a,a≠1
∴e=0=a1−a,a≠0
But the identity is unique. Hence this operation has no identity.