Let B and C be points (12, 19) and (23, 20) respectively. Let A (α,β) be a point such that area of triangle formed by the points A, B and C is 70. Also the slope of the median through A is – 5.
Match the following: ColumnIColumnII(a)Apossiblevalueα+βis(p)2(b)Apossiblevalueβ−2αis(q)27(c)Apossiblevalue3α−β−11is(r)−33(d)Apossiblevalueα−2β+16is(s)47(t)28
A
A) → p, r B) → q,s C) → s D) → q
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B
A) → s,q B) → p,r C) → p D) → r
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C
A) → r B) → q, s C) → q D) → p
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D
A) → p B) → p, q C) → q, s D) → r
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Solution
The correct option is B A) → s,q B) → p,r C) → p D) → r |−197+11β−α|=140,2β+10α=214 Considering the equations 11β–α=337,2β+10α=214 We get α=15,β=22 gives the conclusions