Let $$ be $a$ binary operation on $N$ given by $a b = H C F * (a, b)$ find $22 * 4$

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Solution

$\to 22 * 4 =$ H.C.F of 22 and 4
$∴ 22 = 2 \times 11$
$∴ 4 = 2 \times 2$
Now common factor = 2
$∴$ HCF = 2
$∴ 22 * 4 = 2$

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Let ∗ be a binary operation on N given by a∗b=HCF∗(a,b) find 22∗4

→22∗4= H.C.F of 22 and 4∴22=2×11∴4=2×2Now common factor = 2∴ HCF = 2∴22∗4=2

Let $$ be $a$ binary operation on $N$ given by $a b = H C F * (a, b)$ find $22 * 4$

$\to 22 * 4 =$ H.C.F of 22 and 4
$∴ 22 = 2 \times 11$
$∴ 4 = 2 \times 2$
Now common factor = 2
$∴$ HCF = 2
$∴ 22 * 4 = 2$