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Let O A and O...

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Let be two rays and let be a ray between and such that ∠AOX > ∠XOB.

Let be the bisector of ∠AOB. Prove that ∠AOX − ∠XOB = 2∠COX.

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Solution

Let

From the figure:

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Let be a ray and let and be two rays on the same side of , with between and . Let be the bisector of ∠AOB. Prove that ∠XOA + ∠XOB = 2∠XOC.

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