wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Let C1 and C2 be the centres of the circles x2+y2−2x−2y−2=0 and x2+y2−6x−6y+14=0 respectively. If P and Q are the points of intersection of these circles, then the area (in sq. units) of the quadrilateral PC1QC2 is :

A
4
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
6
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
8
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
9
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 4
Given circle are
x2+y22x2y2=0 and x2+y26x6y+14=0
C1=(1,1),r1=2C2=(3,3),r2=2


As P lies on the circle, so
PC1=2,PC2=2C1C2=4+4=22(PC1)2+(PC2)2=(C1C2)2

C1PC2 is a right angle triangle

So, the area of quadrilateral PC1QC2
=2(12×PC1×PC2)=2(12×2×2)=4 sq. units

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon