We have,
The centre of circle C=(1,1)
Radius r=1
T is the circle centred at point (0,y)
Then, we know that
CT=1+y
So, using distance formula,
CT=√(1−0)2+(1−y)2
⇒CT=√1+(1−y)2
⇒(1+y)2=1+(1−y)2
⇒12+y2+2y=1+12+y2−2y
⇒4y=1
⇒y=14
Hence, this is the
answer.