Question

Let ${\mathrm{C}}_{\mathrm{NaCl}}$ and ${\mathrm{C}}_{{\mathrm{BaSO}}_4}$be the conductances

• A. ${\mathrm{C}}_{\mathrm{NaCl}}\left({\mathrm{T}}_2\right)>{{\mathrm{C}}_{{\mathrm{BaSo}}_4}}_{}\left({\mathrm{T}}_1\right)$for ${\mathrm{T}}_2>{\mathrm{T}}_1$
• B. ${{\mathrm{C}}_{{\mathrm{BaSo}}_4}}_{}\left({\mathrm{T}}_2\right)>{{\mathrm{C}}_{\mathrm{NaCl}}}_{}\left({\mathrm{T}}_1\right)$for ${\mathrm{T}}_2>{\mathrm{T}}_1$
• C. Ionic mobilities of ions from both salts increase with T
• D. ${\mathrm{C}}_{\mathrm{NaCl}}>>{{\mathrm{C}}_{{\mathrm{BaSo}}_4}}_{}$ at a given T

Answer 1

The correct option is D

${\mathrm{C}}_{\mathrm{NaCl}}>>{{\mathrm{C}}_{{\mathrm{BaSo}}_4}}_{}$ at a given T

(D) ${\mathrm{C}}_{\mathrm{NaCl}}>>{\mathrm{C}}_{{\mathrm{BaSo}}_4}$at a given $\mathrm{T}$

$\mathrm{NaCl}$ is more soluble than${\mathrm{BaSO}}_4$, which means it will produce more ions so,
Conductance ($\mathrm{NaCl}$) > Conductance (${\mathrm{BaSO}}_4$).

1. Since $\mathrm{NaCl}$ is a powerful electrolyte, it is completely ionized at ambient temperature.
2. As a result, with an increase in temperature, its ionization does not change ($\mathrm{V}-\mathrm{U}$ charge to a lesser extent).
3. But ${\mathrm{BaSO}}_4$ is a weak electrolyte, the material's conductance increases with temperature.

Hence, Option(D) is correct.