Question

Let current $i=2A$ be flowing in each part of a wire frame as shown in fig. The frame is a combination of two equilateral triangles $ACD$ and $CDE$ of side $1m$. It is placed in uniform magnetic field $B=4T$ acting perpendicular to the plane of frame. The magnitude of magnetic force acting on the frame is

• A. 24 N
• B. zero
• C. 16 N
• D. 8 N

Answer 1

The correct option is A 24 N

${\overrightarrow{F}}_{CAD}={\overrightarrow{F}}_{CED}={\overrightarrow{F}}_{CD}$

Net force on the frame:

$\therefore {\overrightarrow{F}}_{net}=3\times {\overrightarrow{F}}_{CD}$

$=3\times (2\times 1\times 4)=24N$