Let - be the HCF of 24 and 36 - Find two numbers - and - such that -2 4 -3 6 -

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Mathematics

Method of Finding HCF

Let 𝐝 be the...

Question

Let d be the HCF of 24 and 36. Find two numbers a and b such that d= 24a + 36b

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Solution

Solution:-
d = HCF of 24 and 36
To find : a and b such that d = 24a + 36b
Applying Euclid's Division Lemma to 24 and 36, we get
36 = 241 + 12 ...(1)
24 = 212 + 0
Thus, the HCF of 24 and 36 is 12.
From (1), we have,
⇒ 12 = 36 - 24
⇒ 12 = 24(-1) + 36(1)
⇒ 12 = 24a + 36b
Where a = -1 and b = 1

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Let d be the HCF of 24 and 36. Find two numbers a and b ​​​​​such that d= 24a + 36b

Solution:- d = HCF of 24 and 36 To find : a and b such that d = 24a + 36b Applying Euclid's Division Lemma to 24 and 36, we get 36 = 24*1 + 12 ...(1) 24 = 2*12 + 0 Thus, the HCF of 24 and 36 is 12. From (1), we have, ⇒ 12 = 36 - 24 ⇒ 12 = 24(-1) + 36(1) ⇒ 12 = 24a + 36b Where a = -1 and b = 1

Let d be the HCF of 24 and 36. Find two numbers a and b such that d= 24a + 36b

Solution:-
d = HCF of 24 and 36
To find : a and b such that d = 24a + 36b
Applying Euclid's Division Lemma to 24 and 36, we get
36 = 241 + 12 ...(1)
24 = 212 + 0
Thus, the HCF of 24 and 36 is 12.
From (1), we have,
⇒ 12 = 36 - 24
⇒ 12 = 24(-1) + 36(1)
⇒ 12 = 24a + 36b
Where a = -1 and b = 1