CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
302
You visited us 302 times! Enjoying our articles? Unlock Full Access!
Question

Let Δ ABC be an equilateral triangle. Let P be a point on minor arc AB of its circumcircle . Which of the following holds :


A
PC=2PB
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
PC2=PA2+PB2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
PA=PB+PC
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
PC=PA+PB
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is B PC=PA+PB

Draw PA,PB,PC. By Ptolemy's Theorem applied to quadrilateral APBC,

we know that PC×AB=PA×PB+PB×AC.

Since,AB=BC=CA=s, we divide both sides of the last equation by to get the result:PC=PA+PB.


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Energy From the Sea
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon