Let - 3-2x 3-2x 3-2x 3-2x 3-2x 3-2x 3-2x 3-2x 3-2x and K is a factor of - then K-

The correct option is C x^2 or 2x+9 Let Δ=3 2x amp; 3+2x amp; 2+2x 3+2x amp; 3 2x amp; 3+2x 3+2x amp; 3+2x amp; 3 2 ...

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Summation of Determinant

Let Δ= 3-...

Question

Let $Δ^{=}$ $\begin{vmatrix}

3-2x & 3+2x&3+2x \\

3+2x & 3-2x &3+2x \\

3+2x&3+2x & 3-2x

\end{vmatrix} $a n d K i s a f a c t o r o f$ \Delta$ then K=

x^{3}

2 x - 9

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x

2 x + 9

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x^{2}

2 x + 9

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x

3 x + 2

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(3 - 2 x) (3 + 2 x)

= 9 - 4 x^{2}

What must be added to $(x^{3} + 3 x - 8)$ to get $(3 x^{3} + x^{2} + 6)$ ?

f (x) = {\begin{matrix} x^{3} - 3 x + 2 x < 2 x^{3} - 6 x^{2} + 9 x + 2, x \geq 2 \end{matrix}

(2 x - 3)

2 x^{3} - 9 x^{2} + x + k

k

{lim}_{x \to - 2} \frac{x^{3} + 3 x^{2} + 2 x}{x^{2} - x - 6}

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