Let - - - - be such that p - q -p - q - q is a tautology- Then - is equal to -

(p ∨ q) ⇒ q ∼(p ∨ q) ∨ q =(∼ p ∧∼ q) ∨ q =(∼ p ∨ q) ∧(∼ q ∨ q) =(∼ p ∨ q) ∧ T =∼ p ∨ q Now (p ∧ q) Δ(∼ p ∨ q) [ p amp; q ...

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Contra-Positive

Let Δ∈∧, ∨, ⇒...

Question

Let $Δ \in {\land, \lor, \Rightarrow, \Leftrightarrow}$ be such that $(p \land q) Δ ((p \lor q) \Rightarrow q)$ is a tautology. Then $Δ$ is equal to :

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