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Question

Let a=i+j and b=2ik, the point of intersection of the lines r×a=b×a and r×b=a×b is

A
i+j+k
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B
3ij+k
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C
3i+jk
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D
ijk
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Solution

The correct option is D 3i+jk
r×a=b×ar=b+λa
and r×b=a×br=a+μb
For intersection of both the lines, b+λa=a+μb
Comparing coefficients, λ=μ=1
Hence point of intersection is r=a+b=3^i+^j^k

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