Let a=i+j and b=2i−k, the point of intersection of the lines r×a=b×a and r×b=a×b is
A
−i+j+k
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B
3i−j+k
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C
3i+j−k
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D
i−j−k
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Solution
The correct option is D3i+j−k →r×→a=→b×→a⇒→r=→b+λ→a and →r×→b=→a×→b⇒→r=→a+μ→b For intersection of both the lines, →b+λ→a=→a+μ→b Comparing coefficients, λ=μ=1 Hence point of intersection is →r=→a+→b=3^i+^j−^k