Factorization Method Form to Remove Indeterminate Form
Let f x =1+...
Question
Let f(x)={1+2xa;0≤x<1ax,1≤x<2 If limx→1f(x) exist then a is
A
1
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B
−1
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C
2
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D
−2
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Solution
The correct options are B−1 C2 f(x)=1+2xafor0<x<1=axfor1≤x<2Asthefunctioniscontinuousat11+2a=aa2−a−2=0a2−2a+a−2=0a(a−2)+1(a−2)=0a=−1,2 Hence, options 'B' and 'C' are correct.