The correct option is B f is one-one and onto
f(x)=x3+x2+3x+sinx.
⇒f′(x)=3x2+2x+3+cosx≥3x2+2x+3−1, since −1≤cosx≤1
⇒f′(x)≥3x2+2x+2
Now discriminant of above quadratic is =22−4⋅3⋅2<0
Hence f′(x)>0 for all x∈R
Therefore f is one-one function, also every odd degree polynomial
has it's range R. Thus f is an onto function