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Question

Let f:RR where f(x)=2|x|2x then f(x) is

A
periodic function
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B
one one function
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C
many one function
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D
None of these
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Solution

The correct option is C many one function
For x<0
we get
f(x)=2x2x
=0
and
For x>0, we get
f(x)=2x2x
=22x12x
Now f(0)
=2020
=0
=f(1),f(2),f(3)...f(n) nR+
Hence f(x) is a many one function.


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