Let fx-ax-x2- If it has a maximum at x-3 then a is

The correct option is D none of these f(x) = ax+ x^2 f'(x) = ax^2+2x Given x= 3 is nbsp; maximum value of nbsp; f(x) f'( 3)=0 = ...

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Standard XII

Mathematics

Integration of Piecewise Continuous Functions

Let fx=ax+x...

Question

Let $f (x) = \frac{a}{x} + x^{2}$ . If it has a maximum at $x = - 3$ then $a$ is

- 1

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Solution

The correct option is D none of these
$f (x) = \frac{a}{x} + x^{2}$
$f^{'} (x) = - \frac{a}{x^{2}} + 2 x$
Given $x = - 3$ is maximum value of $f (x)$
$f^{'} (- 3) = 0 = - \frac{a}{9} - 6 \Rightarrow a = - 54$

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Let f(x)=ax+x2. If it has a maximum at x=−3 then a is

The correct option is D none of thesef(x)=ax+x2f′(x)=−ax2+2xGiven x=−3 is maximum value of f(x)f′(−3)=0=−a9−6⇒a=−54

Let $f (x) = \frac{a}{x} + x^{2}$ . If it has a maximum at $x = - 3$ then $a$ is

The correct option is D none of these
$f (x) = \frac{a}{x} + x^{2}$
$f^{'} (x) = - \frac{a}{x^{2}} + 2 x$
Given $x = - 3$ is maximum value of $f (x)$
$f^{'} (- 3) = 0 = - \frac{a}{9} - 6 \Rightarrow a = - 54$