Let f(x)=lnmx(m>0) and g(x)=px. Then the equation |f(x)|=g(x) has exactly three solutions for
A
p=me
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
0<p<me
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
0<p<em
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
p<em
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B0<p<me let P(h,k) be a point on f(x)=lnmx then, k=lnmh dydx at point P =1h Equation of tangent at point P L1:y−k=(x−h)h Since, it passes through origin Therefore, k=1 & h=e/m and L1:y=x/h⇒L1:y=mx/e From the figure: |f(x)|=g(x) have exactly three solution when slope of g(x) is less than slope of L1 Therefore, 0<p<m/e Ans: B