Let h(x)=f(x)−(f(x))2+(f(x))3 for every real number 'x', then
A
'h' is increasing whenever 'f' is increasing
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
'h' is increasing wherever 'f' is decreasing
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
'h' is decreasing wherever 'f' is decreasing
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
nothing can be said in general
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct options are B 'h' is decreasing wherever 'f' is decreasing D 'h' is increasing whenever 'f' is increasing h(x)=f(x)−(f(x))2+(f(x))3 h′(x)=f′(x)−2f(x).f′(x)+3(f(x))2.f′(x)=f′(x)(3(f(x))2−2f(x)+1) Now discriminant of 3(f(x))2−2f(x)+1 is negative, therefore it will always positive Hence sign of h′(x) is same as sign of f′(x) Thus if f(x) is increasing then h(x) will also increasing. and if f(x) is decreasing then h(x) will also decreasing..