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Question

Let ex{f(x)f(x)}dx=ϕ(x). Then exf(x)dx is

A
ϕ(x)+exf(x)
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B
ϕ(x)exf(x)
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C
12{ϕ(x)+exf(x)}
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D
12{ϕ(x)+exf(x)}
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Solution

The correct option is B 12{ϕ(x)+exf(x)}
exf(x)dx=exf(x)exf(x)dx=exf(x)+ϕ(x)exf(x)exf(x)dx=12(ϕ(x)+exf(x))

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