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Question

Let (1+x2)2(1+x)n=n+4k=0akxk , If a1,a2,a3ϵ A.P. then the set of values of n is

A
3,4,5
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B
5,6,7
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C
2,3,4
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D
None of these.
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Solution

The correct option is D 2,3,4
a1=C1
a2=2+C2
a3=C3+2×C1
since a1,a2,a3 are in AP
2×a2=a1+a3
n39×n2+26×n24=0
roots of the above equation are 2,3,4

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