Question

Let $m$ be the mid-point and $l$ the upper class limit of a class in a continuous frequency distribution. The lower limit of the class is

• A. $2m+l$
• B. $2m-l$
• C. $m-l$
• D. $m-2l$

Answer 1

Answer: (B)

$2m-l$

Given, $m$ be the mid-point and $l$ the upper class limit of a class in a continuous frequency distribution.
Since, Mid point $=\frac{\text{Lower class limit}+\text{Upper class limit}}{2}$
$\Rightarrow m=\frac{\text{Lower class limit}+l}{2}$
$\Rightarrow 2m=$ Lower class limit $+l$
$\Rightarrow$ Lower class limit $=2m-l$
Hence, option B is correct.