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Byju's Answer
Standard XII
Mathematics
Derivative of Standard Functions
Let fx=sin ...
Question
Let
f
(
x
)
=
sin
4
π
[
x
]
1
+
[
x
]
2
,
w
h
e
r
e
[
×
]
is the greatest integer less than or equal to x, then
A
f(x) is not differentiable at some points
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B
f(x) exists but is different from zero
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C
f(x)=0 for all x
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D
f' (x) =0 but f is not a constant function
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Solution
The correct option is
B
f(x)=0 for all x
f
(
x
)
=
sin
4
π
[
x
]
1
+
[
x
]
2
We know that
[
x
]
given us an integer value
for any x
sin
4
π
[
x
]
=
sin
4
π
n
(
n
ϵ
I
)
for any x
=
0
1
+
[
x
]
2
≥
1
⇒
f
(
x
)
=
0
1
+
[
x
]
2
=
0
for all x
Suggest Corrections
0
Similar questions
Q.
For a real number x, let [x] denote the greatest integer less than or equal to x. Then
f
(
x
)
=
t
a
n
(
π
[
x
−
π
]
)
1
+
[
x
]
2
is:
Q.
For a real number y, let [y] denote the greatest integer less than or equal to y. Then the function
f
(
x
)
=
t
a
n
π
[
(
x
−
π
)
]
1
+
[
x
]
2
Q.
The function
f
x
=
sin
π
x
-
π
4
+
x
2
, where [⋅] denotes the greatest integer function, is
(a) continuous as well as differentiable for all x ∈ R
(b) continuous for all x but not differentiable at some x
(c) differentiable for all x but not continuous at some x.
(d) none of these
Q.
Let
f
(
x
)
=
{
c
o
s
[
x
]
,
x
≥
0
|
x
|
+
a
,
x
<
0
. Then find the value of
a
, so that
lim
x
→
0
f(x) exists, where [x] denotes the greatest integer function less than or equal to x.
Q.
Examine for continuity and differentiability at the points
x
=
1
,
x
=
2
, the function
f
defined by
f
(
x
)
=
{
x
[
x
]
,
0
≤
x
<
2
(
x
−
1
)
[
x
]
,
2
≤
x
≤
3
where
[
x
]
=
greatest integer less than or equal to
x
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