Let n u -700-n A -200- n B -300- n A- B -100- then n A- B- -

The correct option is C 300 n ( A' ∩ B' )=n ( A∪ nbsp;B )' nbsp; =n ( u ) n ( A∪ B ) nbsp; =n ( u ) {n ( A )+n ( B ) n ( A∩ B ...

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Let n u =70...

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Let $n (u) = 700, n (A) = 200, n (B) = 300, n (A \cap B) = 100$ , then $n (A^{'} \cap B^{'}) =$

400

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600

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300

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