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Question

Let P(3,2,6) be a point in space and Q be a point on the line
r=(ij+2k)+μ(3i+j+5k)
Then the value of μ for which the vector PQ is parallel to x4y+3z=1 is

A
14
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B
14
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C
18
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D
18
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Solution

The correct option is B 14
Let O be the origin, as Q lies on the given line,
OQ=ij+2k+μ(3i+j+5k)
Also OP=3i+2j+6k.
As PQ is parallel to the plane x4y+3z=1.
PQ(i4j+3k)=0
(OQOP)(i4j+3k)=0
(1+4+6)+μ(34+15)(38+18)=0
11+8 μ13=0
μ=14
Ans: A

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