Let →a,→b,→c are three non-coplanar vectors such that →r1=→a−→b+→c,→r2=→b+→c−→a,→r3=→c+→a+→b, →r=2→a−3→b+4→c. If →r=λ1→r1+λ2→r2+λ3→r3 then
A
λ1=7
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
λ1+λ3=3
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
λ1+λ2+λ3=4
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
λ3+λ2=2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct options are Bλ1+λ3=3 Cλ1+λ2+λ3=4 →r1=→a−→b+→c,→r2=→b+→c−→a,→r3=→c+→a+→b,→r=2→a−3→b+4→c→r=λ1→r1+λ2→r2+λ3→r3=λ1(→a−→b+→c)+λ2(→b+→c−→a)+λ3(→c+→a+→b)=(λ1−λ2+λ3)→a+(λ2−λ1+λ3)→b+(λ1+λ2+λ3)→c