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Question

Let a,b,c are three non-coplanar vectors such that r1=ab+c,r2=b+ca,r3=c+a+b, r=2a3b+4c. If r=λ1r1+λ2r2+λ3r3 then

A
λ1=7
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B
λ1+λ3=3
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C
λ1+λ2+λ3=4
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D
λ3+λ2=2
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Solution

The correct options are
B λ1+λ3=3
C λ1+λ2+λ3=4
r1=ab+c,r2=b+ca,r3=c+a+b,r=2a3b+4cr=λ1r1+λ2r2+λ3r3=λ1(ab+c)+λ2(b+ca)+λ3(c+a+b)=(λ1λ2+λ3)a+(λ2λ1+λ3)b+(λ1+λ2+λ3)c

Also r=2a3b+4c

On comparing, we get
λ1λ2+λ3=2 ...(1)
λ1+λ2+λ3=3 ...(2)
λ1+λ2+λ3=4 ...(3)

Adding (1) and (3), we get
2(λ1+λ3)=6λ1+λ3=3

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