Let →V=2→i+→j−→k and →W=→i+3→k. If →U is a unit vector then the maximum value of the scalar triple product [→U→V→W] is
A
−1
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B
√10+√6
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C
√59
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D
√60
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Solution
The correct option is C√59 [→U→V−→W]=→U⋅(→V×−→W) =→U.[(2^i+^j−^k)×(^i+3^k)] =→U.(3^i−7^j−^k) The maximum value of →a.→b is ab. So, similarly, the maximum value of the above expression will be √59