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Question

Let E1 and E2 be two independent events such that P(E1)=P1 and P(E2)=P2. Describe in words of the events whose probabilities are

(i) P1P2

(ii) (1P1)P2

(iii) 1(1P1)(1P2)

(iv) P1+P22P1P2

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Solution

P(E1)=P1 and P(E2)=P2

(i) P1P2P(E1).P(E2)=P(E1E2)

So, E1 and E2 occur.

(ii) (1P1)P2=P(E1).P(E2)=P(E1E2)
So, E1 does not occur but E2 occurs.

(iii) 1(1P1)(1P2)=1P(E1)P(E2)=1P(E1E2)=1[1P(E1E2)]=P(E1E2)
So, either E1 or E2 or both E1 and E2 occurs.

(iv) P1+P22P1P2=P(E1)+P(E2)2P(E1).P(E2)=P(E1)+P(E2)2P(E1E2)=P(E1E2)P(E1E2)
So, either E1 or E2 occurs but not both.


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