Let E={1,2,3,4} and F={1,2}, then the number of onto functions from E to F is
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Solution
E={1,2,3,4} and F={1,2},
If n(E)=m and n(F)=n, where 1≤n≤m, then number of onto functions from A to B =nm−(nC1(n−1)m−nC2(n−2)m+…) (∵m=4,n=2,m>n) =24−(2C1(2−1)4) =16−2=14