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Question

Let ef(x)=nx. If g(x) is the inverse function of f(x), then g(x) equals to:

A
eex+x(ex+1)
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B
ex+x
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C
ex+ex
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D
ex+1
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Solution

The correct option is A eex+x(ex+1)
ef(x)=lnx
Taking log on both sides.
f(x)lne=ln(lnx)f(x)=ln(lnx)Let,f(x)=yy=ln(lnx)ln(x)=eyx=eeyReplacexbyy&ybyxy=eexg(x)=eexg(x)=eex.exg(x)=e(ex+x)(ex+1)

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