Question

Let $E=\{x:x^2+5x-6=0\}$ and $F=\{-6,1\}$. Then :

• A. $E=F$
• B. $E\ne F$
• C. $E\subset F$
• D. $F\subset E$

Answer 1

The correct option is A $E=F$

For set $E$

$x^2+5x-6=0x^2+6x-x-6=0x(x+6)-1(+6)=0(x-1)(x+6)=0\Rightarrow x=-6,1\Rightarrow E=\{-6,1\}$

$\Rightarrow E=F$

So option $A$ is correct.