Let A - -102 -160- -160- -160-314- B - 0-251-31 and C - 1-5 -160- -160- -160-26 -160- -160-0-4- Compute 2A minus- 3B - 4C-

Here,2A 3B+4C=2 102314 30 251 31+41 5260 4 #8658;2A 3B+4C= 204628 0 6153 93+4 208240 16 #8658;2A 3B+4C= 2 0+40+6 204 15+86 3+242+9+08 3 16 #8658;2A 3B+4C= ...

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Byju's Answer

Standard XII

Mathematics

Properties of Inequalities

Let A = -102 ...

Question

Let A = $\"[\"\begin{matrix} - 1 & 0 & 2 \\ 3 & 1 & 4 \end{matrix}\"]\",$ B = $\"[\"\begin{matrix} 0 & - 2 & 5 \\ 1 & - 3 & 1 \end{matrix}\"]\"$ and C = $\"[\"\begin{matrix} 1 & - 5 & 2 \\ 6 & 0 & - 4 \end{matrix}\"]\"$ . Compute 2A − 3B + 4C.

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Solution

$Here, 2 A - 3 B + 4 C = 2 [\begin{matrix} - 1 & 0 & 2 \\ 3 & 1 & 4 \end{matrix}] - 3 [\begin{matrix} 0 & - 2 & 5 \\ 1 & - 3 & 1 \end{matrix}] + 4 [\begin{matrix} 1 & - 5 & 2 \\ 6 & 0 & - 4 \end{matrix}] \Rightarrow 2 A - 3 B + 4 C = [\begin{matrix} - 2 & 0 & 4 \\ 6 & 2 & 8 \end{matrix}] - [\begin{matrix} 0 & - 6 & 15 \\ 3 & - 9 & 3 \end{matrix}] + [\begin{matrix} 4 & - 20 & 8 \\ 24 & 0 & - 16 \end{matrix}] \Rightarrow 2 A - 3 B + 4 C = [\begin{matrix} - 2 - 0 + 4 & 0 + 6 - 20 & 4 - 15 + 8 \\ 6 - 3 + 24 & 2 + 9 + 0 & 8 - 3 - 16 \end{matrix}] \Rightarrow 2 A - 3 B + 4 C = [\begin{matrix} 2 & - 14 & - 3 \\ 27 & 11 & - 11 \end{matrix}]$

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Similar questions

Q. Let A =

[\begin{matrix} - 1 & 0 & 2 \\ 3 & 1 & 4 \end{matrix}],

B =

[\begin{matrix} 0 & - 2 & 5 \\ 1 & - 3 & 1 \end{matrix}]

and C =

[\begin{matrix} 1 & - 5 & 2 \\ 6 & 0 & - 4 \end{matrix}]

. Compute 2A − 3B + 4C.

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A = [\begin{matrix} - 1 & 0 & 2 3 & 1 & 4 \end{matrix}], B = [\begin{matrix} 0 & - 2 & 5 1 & - 3 & 1 \end{matrix}]

and

C = [\begin{matrix} 1 & - 5 & - 2 6 & 0 & - 4 \end{matrix}],

then

2 A - 3 B + 4 C

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2 \to a + 3 \to b + 4 \to c = 0 \Rightarrow \to a \times \to b + \to b \times \to c + \to c \times \to a =

Q. From the sum of

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and

\frac{2 a}{3} + \frac{3 b}{4} + \frac{4 c}{5}

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Q. If

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Let A = -102 314, B = 0-251-31 and C = 1-5 26 0-4. Compute 2A − 3B + 4C.

Here,2A-3B+4C=2-102314-30-251-31+41-5260-4⇒2A-3B+4C=-204628-0-6153-93+4-208240-16⇒2A-3B+4C=-2-0+40+6-204-15+86-3+242+9+08-3-16⇒2A-3B+4C=2-14-32711-11

Let A = $\"[\"\begin{matrix} - 1 & 0 & 2 \\ 3 & 1 & 4 \end{matrix}\"]\",$ B = $\"[\"\begin{matrix} 0 & - 2 & 5 \\ 1 & - 3 & 1 \end{matrix}\"]\"$ and C = $\"[\"\begin{matrix} 1 & - 5 & 2 \\ 6 & 0 & - 4 \end{matrix}\"]\"$ . Compute 2A − 3B + 4C.