Question

Let $f\left(0\right)=1,f\left(1\right)=2.72$, then the Trapezoidal rule gives approximate value of ${\int }_0^{1}f\left(x\right)dx$

• A. $3.72$
• B. $1.86$
• C. $1.72$
• D. $0.86$

Answer 1

Answer: (B)

$1.86$

By Trapezoidal rule, we have ${\int }_0^{1}f\left(x\right)dx=\frac{1}{2}\left[f\right(0)+f(1\left)\right]$
$=\frac{3.72}{2}=1.86$