Question

Let $f:[0,\infty )\to R$ be a continuous function such that
$f\left(x\right)=1-2x+\underset{0}{\overset{x}{\int }}{e}^{x-t}f\left(t\right)dt$ for all $x\in [0,\infty )$. Then, which of the following statement(s) is (are) TRUE?

• A. The curve $y=f\left(x\right)$ passes through the point $(1,2)$
• B. The curve $y=f\left(x\right)$ passes through the point $(2,-1)$
• C. The area of the region $\left\{\right(x,y)\in [0,1]\times R:f(x)\le y\le \sqrt{1-x^2}\}$ is $\frac{\pi -2}{4}$
• D. The area of the region $\left\{\right(x,y)\in [0,1]\times R:f(x)\le y\le \sqrt{1-x^2}\}$ is $\frac{\pi -1}{4}$

Answer 1

Answer: (B), (C)

The correct options are
B The curve $y=f\left(x\right)$ passes through the point $(2,-1)$
C The area of the region $\left\{\right(x,y)\in [0,1]\times R:f(x)\le y\le \sqrt{1-x^2}\}$ is $\frac{\pi -2}{4}$

$f\left(x\right)=1-2x+e^x\underset{0}{\overset{x}{\int }}{e}^{-t}f\left(t\right)dt\cdots \left(i\right)$
$\Rightarrow f^{\prime }\left(x\right)=-2+e^x\underset{0}{\overset{x}{\int }}{e}^{-t}f\left(t\right)dt+e^x{e}^{-x}f\left(x\right)$
$\Rightarrow f^{\prime }\left(x\right)=-2+f\left(x\right)-1+2x+f\left(x\right)\left[From\right(i\left)\right]$
$\Rightarrow f^{\prime }\left(x\right)-2f\left(x\right)=2x-3$
which is a linear differential equation.

$\text{IF}=e^{-2x}$
$\therefore f\left(x\right)\cdot e^{-2x}=\int (2x-3)e^{-2x}dx$
$\Rightarrow f\left(x\right)\cdot e^{-2x}=\frac{(2x-3)e^{-2x}}{-2}-\frac{e^{-2x}}{2}+C$

$\text{From}\left(i\right),f\left(0\right)=1$
$\Rightarrow f\left(x\right)=1-x$
$y=f\left(x\right)$ passes through $(2,-1)$.


Required area
$=\underset{0}{\overset{1}{\int }}(\sqrt{1-x^2}-(1-x\left)\right)dx$
$=\frac{\pi }{4}-\frac{1}{2}=\frac{\pi -2}{4}$