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How to Find the Inverse of a Function

Let f : [0,3]...

Question

Let f : [0,3] is defined by $f (x) = x^{2} + x + 1$ then $f^{- 1} (x)$

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Solution

$f (x) = x^{2} + x + 1$
$y = x^{2} + x + 1$
Swapping $x$ and $y$ ,
$x = y^{2} + y + 1$
$f^{- 1} (x)$ does not exist

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