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Question

Let f = {(1, 1), (2, 3), (0, –1), (–1, –3)} be a function from Z to Z defined by f(x) = ax + b, for some integers a, b. Determine a, b.

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Solution

f = {(1, 1), (2, 3), (0, –1), (–1, –3)}

f(x) = ax + b

(1, 1) f

f(1) = 1

a × 1 + b = 1

a + b = 1

(0, –1) f

f(0) = –1

a × 0 + b = –1

b = –1

On substituting b = –1 in a + b = 1, we obtain a + (–1) = 1 a = 1 + 1 = 2.

Thus, the respective values of a and b are 2 and –1.


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