Let f={(1,1),(2,3),(0,−1),(−1,−3)} be a function from Z to Z defined by f(x)=ax+b for some integers a,b. Determine a,b.
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Solution
f={(1,1),(2,3),(0,−1),(−1,−3)} f(x)=ax+b (1,1)∈f ⇒f(1)=1 ⇒a×1+b=1 ⇒a+b=1 .....(1) (0,−1)∈f ⇒f(0)=−1 ⇒a×0+b=−1 ⇒b=−1 On substituting b=−1 in eqn (1), we get a+(−1)=1 ⇒a=1+1=2 Thus the respective values of a and b are 2 and −1