Let $F_{1}$ be the set of all parallelograms, $F_{2}$ the set of rectangles, $F_{3}$ the set of rhombuses, $F_{4}$ the set of squares and $F_{5}$ the set of trapeziums in a plane, then $F_{1}$ is equal to

$F_{2} \cup F_{3} \cup F_{4} \cup F_{5}$

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$F_{2} \cup F_{3} \cup F_{4} \cup F_{1}$

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$F_{3} \cap F_{4}$

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$F_{2} \cap F_{1}$

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Solution

The correct option is B
$F_{2} \cup F_{3} \cup F_{4} \cup F_{1}$

Every rectangle, rhombus and square in a plane is a parallelogram but every trapezium is not a parallelogram.

Hence,

$F_{1}$ = $F_{2} \cup F_{3} \cup F_{4} \cup F_{1}$

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Similar questions

Let $F_{1}$ be the set of all parallelograms, $F_{2}$ the set of all reactangles, $F_{3}$ the set of all rhombuses, $F_{4}$ the set of all sqauares and $F_{5}$ the set of trapeziums in a plane. Then $F_{1}$ may be equal to

Q. Let F₁ be the set of all parallelograms, F₂the set of all rectangles, F₃the set of all rhombuses, F₄the set of all squares and F₅the set of trapeziums in a plane. Then F₁ may be equal to

(a)

F_{2} \cap F_{3}

(b)

F_{3} \cap F_{4}

(c)

F_{2} \cup F_{3}

(d)

F_{2} \cup F_{3} \cup F_{4} \cup F_{1}

Let $F_{1}$ be the set of all parallelograms, $F_{2}$ the set of rectangles, $F_{3}$ the set of rhombuses, $F_{4}$ the set of squares and $F_{5}$ the set of trapeziums in a plane, then $F_{1}$ is equal to